How do you write the equation of a line given (6,-3),(-2,-3)?

3 Answers
Jun 7, 2017

#y=-3#

Explanation:

First, we need to determine the slope of the line. The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#

Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(-3) - color(blue)(-3))/(color(red)(-2) - color(blue)(6)) = (color(red)(-3) + color(blue)(3))/(color(red)(-2) + color(blue)(-6)) = 0/-8 =0#

Next we can use the point-slope formula to write an equation for the line. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #(color(red)(x_1, y_1))# is a point the line passes through. Substituting the slope we calculated and the values from the second point in the problem gives:

#(y - color(red)(-3)) = color(blue)(0)(x - color(red)(6))#

#(y + color(red)(3)) = 0#

#y=-3#

Jun 7, 2017

#y=-3#

Explanation:

Begin by finding the slope using the slope formula:
#m=(y_2-y_1)/(x_2-x_1)#

Let #(6,-3)->(color(red)(x_1),color(blue)(y_1))# and #(-2,-3)->(color(red)(x_2),color(blue)(y_2))#

Find the slope:

#m=color(blue)(-3-(-3))/color(red)(-2-6)=0/-8=0#

The equation of the line can be found using the point-slope formula: #y-y_1=m(x-x_1)# where #m# is the slope and #(x_1,y_1)# is a point on the function. Since we have a slope and two points (we can choose either one. I will use #(-2,-3)#), we can substitute this information like so:

#y-(-3)=0(x-(-2))#

Simplify:

#y+3=0x+0#

#y+3=0#

Write in #y=mx+b# form by isolating the #y#

#y+cancel(3-3)=0-3#

#y=-3# <-- Equation of the line

Jun 7, 2017

See a solution process below:

Explanation:

Because both of the #y# values are the same and equal to #color(red)(-3)# we know, by definition this is a horizontal line.

Horizontal lines have the form:

#y = color(red)(a)# where #a# is the value of #y# which is the same for each and every value of #x#.

Therefore, for this problem, an equation is:

#y = color(red)(-3)#