Question

How do you write the equation of a line in point slope form and slope intercept form given point (-1, 6) and has a slope of -4?

Answer 1

The main formula of a line is;
`y=ax+b`

We should use one point to find the real equation. If we use (-1,6) point;
`y= ax+b => 6=-a+b`;
a is the slope of the equation, we found that as `-4`;
`6=(-4*-1) + b => 6=4 +b => b=2`;
So the equation of the line will be;
`y=ax+b => ul (y= -4x+2)`