# How do you write the equation of a line that passes through (-6, 1) with a slope of 1/3?

Nov 25, 2016

$y = \frac{1}{3} x + 3$

#### Explanation:

The equation of a straight line of slope $\text{ "a" }$passing through
$\text{ }$
$\left({x}_{0} , {y}_{0}\right)$ is:
$\text{ }$
$y - {y}_{0} = a \left(x - {x}_{0}\right)$
$\text{ }$
$\Rightarrow y - 1 = \frac{1}{3} \left(x + 6\right)$
$\text{ }$
$\Rightarrow y - 1 = \frac{1}{3} x + \frac{6}{3}$
$\text{ }$
$\Rightarrow y = \frac{1}{3} x + 2 + 1$
$\text{ }$
$\Rightarrow y = \frac{1}{3} x + 3$