Question

How do you write the equation of the line passing through `(-3, 10)`, and perpendicular to `-3x-6y=-12` in slope-intercept form?

Answer 1

`y= 2x +16`

Explanation:

Solve the given equation for y, it would be

`y=(-1/2)x +2`. This shows that slope of this line is `-1/2`

Slope of the line perpendicular to this would be 2. Since this line passes through (-3,10), the point slope form of this line would be

`y-10=2 (x+3)`. Now solve this for y,

`y= 2x +16`, which is the required slope, intercept form.