How do you write the equation of the line that passes through (1, 3) and (4, 4) in standard form?

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Answer 1 · 2018-04-13T02:34:09

#y = (x/3) + (8/3)#

#"Known two points on a line, we can write the equation of the line as under "#

#(y-y_1) / (y_2-y_1) = (x-x_1) / (x_2 - x_1)#

#"Given : (x_1,y_1) = (1,3), (x_2, y_2) = (4,4)#

#(y - 3) / (4-3) = (x-1) / (4-1)#

#(y-3) = (x-1)/3#

#3y - 9 = x - 1#

#3y = x -1 + 9 = x + 8#

#y = (x/3) + (8/3)#

#"It's in the form ", y = mx + c' " where"#

#"Slope " m = 1/3, "y-intercept " = 8/3#