How do you write the equation of the line with point (3, 6) and (0, –3) ?

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Answer 1 · 2016-07-26T13:56:14

The slope-intercept equation of the line would be #y=3x-3#

The slope-intercept form of the equation of the line is #y=mx+b#
where #m=# slope and #b=# the y intercept

Using the points (3,6) and (0,-3)

#m=(y_2-y_1)/(x_2-x_1)#

#x_1=3#
#y_1=6#
#x_2=0#
#y_2=-3#

#m = (-3-6)/(0-3)#

#m = (-9)/(-3)#

#m=3#

Now use the point slope formula to solve for the equation of the line.

#(y-y_1)=m(x-x_1)#

#m=3#
#x_1=0#
#y_1=-3#

#(y-y_1)=m(x-x_1)#

#(y-(-3))=-3(x-0)#

#y+3=-3x#

#y cancel(+3) cancel(-3)=3x -3#

#y=3x-3#