# How do you write the equation of the line with point P(-10,1) with slope -5?

Apr 25, 2016

$y - 1 = - 5 \left(x + 10\right)$

#### Explanation:

Use the point-slope form:
$y - {y}_{1} = m \left(x - {x}_{1}\right)$

We know that in the slope-intercept formula ($y = m x + b$), the $m$ value is the slope. Similarly, in point-slope form, the $m$ is also the slope.

We are given that the slope is equal to -5. Also, there's point P(-10,1). The part where we have ${y}_{1}$ and ${x}_{1}$, we can replace it with the corresponding x- and y-coordinates. The x-coordinate in this case would be -10 and the y-ccordinate in this case would be 1. Let's substitute all of these values into its corresponding area in the formula.

$y - 1 = - 5 \left(x - \left(- 10\right)\right)$
Which can also be written as $y - 1 = - 5 \left(x + 10\right)$