# How do you write the equation of the parabola in vertex form given the vertex (-4,3), point (4,131)?

##### 1 Answer
Apr 20, 2016

The equation of the parabola is $y = 2 {\left(x + 4\right)}^{2} + 3$

#### Explanation:

The equation of parabola in vertex form with vertex at(-4,3) is $y = a {\left(x + 4\right)}^{2} + 3$ The point (4,131) is on the parabola , so it satisfies the equation.$\therefore 131 = a \cdot {\left(4 + 4\right)}^{2} + 3 \mathmr{and} a = \frac{128}{64} = 2$Hence the equation of the parabola is $y = 2 {\left(x + 4\right)}^{2} + 3$ graph{2(x+4)^2+3 [-10, 10, -5, 5]}[Ans]