Question

How do you write the equation of the parabola in vertex form given the vertex (-4,3), point (4,131)?

Answer 1

The equation of the parabola is `y=2(x+4)^2+3`

Explanation:

The equation of parabola in vertex form with vertex at(-4,3) is `y=a(x+4)^2+3` The point (4,131) is on the parabola , so it satisfies the equation.`:.131=a*(4+4)^2+3 or a =128/64=2`Hence the equation of the parabola is `y=2(x+4)^2+3` graph{2(x+4)^2+3 [-10, 10, -5, 5]}[Ans]