How do you write the equation of the parabola in vertex form given the vertex (9,-2) and point (12,16)?

1 Answer
Apr 2, 2016

#y=2(X-9)^2-2#

Explanation:

The general vertex form is
#color(white)("XXX")y=m(x-a)^2+b# for a parabola with vertex at #(a,b)#

So a parabola with vertex at #(9,-2)# will have the form:
#color(white)("XXX")y=m(x-9)^2+(-2)#

Since #(x,y)=(12,16)# is given as a solution to this equation
#color(white)("XXX")16=m(12-9)^2-2#

#color(white)("XXX")16=9m-2#

#color(white)("XXX")m=2#
and
the equation of the parabola is
#color(white)("XXX")y=2(x-9)^2-2#
graph{2(x-9)^2-2 [1.37, 13.854, -2.37, 3.87]}