# How do you write the expression (x+6)(x-2) as a polynomial in standard form?

Mar 21, 2016

The final answer: ${x}^{2} + 4 x - 12$

#### Explanation:

To write the expression $\left(x + 6\right) \left(x - 2\right)$ in standard form you can FOIL (First Outer Inner Last).

$x \times x = {x}^{2}$

$x \times \left(- 2\right) = - 2 x$

$6 \times x = 6 x$

$6 \times \left(- 2\right) = - 12$

After foiling completely you get:

${x}^{2} - 2 x + 6 x - 12$

Next, you combine like terms.

$- 2 x + 6 x = 4 x$

There are no other like terms. Therefore, your final answer is

${x}^{2} + 4 x - 12$

Mar 21, 2016

It's really a lot easier to see the FOIL method than explain.

Then, once foiled out, combine like terms.
Your final answer will be, x^2 +4x -12