How do you write the first five terms of the sequence #3n^2+4# using the nth term rule?

1 Answer
Feb 29, 2016

7 , 16 , 31 , 52 , 79

Explanation:

#3n^2 + 4 " is the nth term rule "#

To generate the terms in the sequence , substitute in appropriate values for n and evaluate.

Here use n = 1,2,3,4,5 .

#n = 1 : 3(1)^2 + 4 = 3 + 4 = 7 #

# n = 2 : 3(2)^2 + 4 = 12 + 4 = 16 #

# n = 3 : 3(3)^2 + 4 = 27 + 4 = 31 #

I'm sure you can manage the last 2 yourself.