# How do you write the first five terms of the sequence a_n=3n+1?

Aug 10, 2018

$4 , 7 , 10 , 13 , 16$

#### Explanation:

$\text{to obtain the first 5 terms substitute "n=1,2,3,4,5}$
$\text{into } {a}_{n}$

${a}_{1} = \left(3 \times 1\right) + 1 = 3 + 1 = 4$

${a}_{2} = \left(3 \times 2\right) + 1 = 6 + 1 = 7$

${a}_{3} = \left(3 \times 3\right) + 1 = 9 + 1 = 10$

${a}_{4} = \left(3 \times 4\right) + 1 = 12 + 1 = 13$

${a}_{5} = \left(3 \times 5\right) + 1 = 15 + 1 = 16$

Aug 10, 2018

The first five terms are $: 4 , 7 , 10 , 13 , 16.$

#### Explanation:

Here ,

${a}_{n} = 3 n + 1$

$n = 1 \implies {a}_{1} = 3 \left(1\right) + 1 = 3 + 1 = 4$

$n = 2 \implies {a}_{2} = 3 \left(2\right) + 1 = 6 + 1 = 7$

$n = 3 \implies {a}_{3} = 3 \left(3\right) + 1 = 9 + 1 = 10$

$n = 4 \implies {a}_{4} = 3 \left(4\right) + 1 = 12 + 1 = 13$

$n = 5 \implies {a}_{5} = 3 \left(5\right) + 1 = 15 + 1 = 16$

Hence ,the first five terms are $: 4 , 7 , 10 , 13 , 16.$