# How do you write the nuclear equation for the beta decay of francium-223.?

Apr 18, 2016

${\text{_ 87^223Fr -> ""_ 88^223Ra + ""_ -1^0e + }}_{0}^{0} \nu$

#### Explanation:

$\beta$-decay is the decay of a neutron into a proton, which keeps the total mass the same, but increases the number of protons by $1$. $\beta$-decay does this by releasing an electron, which conserves charge, and a neutrino.

Francium-223 has an atomic number of 87, so is written as

""_ 87^223Fr

If the atomic number then increases by $1$ to become $88$, then it is a new element. Looking at the periodic table, element $88$ is radium, $R a$.

In the form of an equation, this is shown as

${\text{_ 87^223Fr -> ""_ 88^223Ra + ""_ -1^0e + }}_{0}^{0} \nu$

You can check this is correct by adding up the top numbers on each side and equating them, and doing the same with the bottom numbers.

$223 = 223 + 0 + 0$
$87 + 88 + \left(- 1\right) + 0$