# How do you write the point slope form of an equation for a lint that passes through (-3,6) with m=0?

Jul 2, 2017

$y - 6 = 0 \left(x - \left(- 3\right)\right)$

#### Explanation:

Point slope form is this: $y - {y}_{1} = m \left(x - {x}_{1}\right)$, where the line passes through the point $\left({x}_{1} , {y}_{1}\right)$, and has a slope of $m$.

Plugging in the values, we get:
$y - 6 = 0 \left(x - \left(- 3\right)\right)$

This is also just a horizontal line, or $y = 6$.