How do you write the quadratic function in intercept form given x intercepts -2,2 and point (-4,8)?

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Answer 1 · 2017-08-27T06:57:48

#y=2/3(x^2-4)#

A quadratic equation in intercept form given #x# intercepts #-2,2# is

#y=a(x-(-2))(x-2)# or #y=a(x+2)(x-2)#

i.e. #y=a(x^2-4)#

As it passes through #(-4,8)#, we have

#8=a((-4)^2-4)# or #12a=8# or #a=8/12=2/3#

Hence, quadratic equation is #y=2/3(x^2-4)#

graph{(2/3(x^2-4)-y)((x+4)^2+(y-8)^2-0.04)=0 [-9.42, 10.58, -1.56, 8.44]}