How do you write the quadratic function in intercept form given x intercepts -5,0 and point (-3,18)?

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Answer 1 · 2017-06-28T05:22:52

#y=-3x(x+5)#

As the quadratic function has #0# and #-5# as #x#-intercepts, it is of the form

#y=a(x-0)(x-(-5))# or #y=ax(x+5)#

As it passes through #(-3,18)#, we have

#18=axx(-3)(-3+5)#

or #18=-6a# i.e. #a=-3#

and quadratic function is

#y=-3x(x+5)#
graph{-3x(x+5) [-13, 7, -10, 20]}