Question

How do you write the quadratic in vertex form given `y=-2x^2+6x+1`?

Answer 1

Standard form`f(x) = - 2x^2 + 6x + 1`
Vertex form `f(x) = (x - b/(2a))^2 + f(-b/(2a))`

`-b/2a = -6/-4 = 3/2`

`f(3/2) = -2(9/4) + 6(3/2) + 1 = 11/2`

Vertex form`f(x) = (x - 3/2)^2 + 11/2`