Question

How do you write the quadratic in vertex form given `y = –x^2 +12x – 4`?

Answer 1

(-b/2a) = -12/-2 = 6

f(-b/2a) = f(6) = -36 + 72 - 4 = 32

Vertex form: f(x) = - (x - 6)^2 + 32

Check. Develop: - (x^2 - 12x + 36) + 32 = - x^2 + 12x - 4. Correct