# How do you write the slope-intercept form of the line with a slope of -2 and going through the point (3, 2)?

Feb 1, 2016

$y = - 2 x + 8$

#### Explanation:

Given a slope of $m = - 2$ through the point $\left(\overline{x} , \overline{y}\right) = \left(3 , 2\right)$
we can write the linear equation in slope-point form as
$\textcolor{w h i t e}{\text{XXX}} y - \overline{y} = m \left(x - \overline{x}\right)$

$\textcolor{w h i t e}{\text{XXX}} y - 2 = \left(- 2\right) \left(x - 3\right)$

We have been asked to convert this into slope-intercept form:
$\textcolor{w h i t e}{\text{XXX}} y = m x + b$

Simplifying the right side of our slope-point form:
$\textcolor{w h i t e}{\text{XXX}} y - 2 = - 2 x + 6$

Adding $2$ to both sides to isolate the $y$
$\textcolor{w h i t e}{\text{XXX}} y = - 2 x + 8$
$\textcolor{w h i t e}{\text{XXXXXXXXXXX}}$which is in the slope-intercept form