How do you write the slope-intercept form of the line with a slope of -2 and going through the point (3, 2)?

1 Answer
Feb 1, 2016

Answer:

#y=-2x+8#

Explanation:

Given a slope of #m=-2# through the point #(barx,bary)=(3,2)#
we can write the linear equation in slope-point form as
#color(white)("XXX")y-bary=m(x-barx)#

#color(white)("XXX")y-2 =(-2)(x-3)#

We have been asked to convert this into slope-intercept form:
#color(white)("XXX")y=mx+b#

Simplifying the right side of our slope-point form:
#color(white)("XXX")y-2 = -2x+6#

Adding #2# to both sides to isolate the #y#
#color(white)("XXX")y=-2x+8#
#color(white)("XXXXXXXXXXX")#which is in the slope-intercept form