Question

How do you write the standard form of a line given x intercept = -5, y intercept = -5?

Answer 1

`x+y=-5`

Explanation:

`"the equation of a line in "color(blue)"standard form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))`

`"where A is a positive integer and B, C are integers"`

`"obtain the equation in "color(blue)"slope-intercept form"`

`•color(white)(x)y=mx+b`

`"where m is the slope and b the y-intercept"`

`"to calculate the slope use the "color(blue)"gradient formula"`

`•color(white)(x)m=(y_2-y_1)/(x_2-x_1)`

`"let "(x_1,y_1)=(-5,0)" and "(x_2,y_2)=(0,-5)`

`rArrm=(-5-0)/(0-(-5))=(-5)/5=-1`

`"using "m=-1" and "b=-5`

`rArry=-x-5larrcolor(red)"in slope-intercept form"`

`"add x to both sides"`

`x+y=cancel(-x)cancel(+x)-5`

`rArrx+y=-5larrcolor(red)"in standard form"`