How do you write the standard Form of the parabola equation given Vertex (3 , -3) Focus (3 , -9/4)?
1 Answer
May 24, 2017
#y=1/3(x^2-6x)#
Explanation:
Look at the diagram
Given -
Vertex
Focus
The parabola is facing up. Hence the equation-
#(x-h)^2=4a(y-k)#
Where -
#h=3#
#k=-3#
#a=3/4# [Distance between vertx and focus]
#(x-3)^2=4 xx 3/4 xx (y-(-3))#
#x^2-6x+9)=3(y+3)=3y+9#
#3y+9=x^2-6x+9#
#3y=x^2-6xcancel(+9)cancel(-9)#
#y=1/3(x^2-6x)#
