# How do you write the standard Form of the parabola equation given Vertex (3 , -3) Focus (3 , -9/4)?

##### 1 Answer

May 24, 2017

#y=1/3(x^2-6x)#

#### Explanation:

Look at the diagram

Given -

Vertex

Focus

The parabola is facing up. Hence the equation-

#(x-h)^2=4a(y-k)#

Where -

#h=3#

#k=-3#

#a=3/4# [Distance between vertx and focus]

#(x-3)^2=4 xx 3/4 xx (y-(-3))#

#x^2-6x+9)=3(y+3)=3y+9#

#3y+9=x^2-6x+9#

#3y=x^2-6xcancel(+9)cancel(-9)#

#y=1/3(x^2-6x)#