# How do you write the trigonometric form into a complex number in standard form 6(cos(230^o 30')+isin(230^o 30')?

Oct 26, 2016

$\cos \left({230}^{o} 30 '\right) = - 0.6361$ in standard form is $- 3.8166 - 4.6296 i$

#### Explanation:

As $\cos \left({230}^{o} 30 '\right) = - 0.6361$ and

$\sin \left({230}^{o} 30 '\right) = - 0.7716$

$6 \left(\cos \left({230}^{o} 30 '\right) + i \sin \left({230}^{o} 30 '\right)\right)$

= $6 \left(- 0.6361 - i 0.7716\right)$

= $- 3.8166 - 4.6296 i$