# How do you write the Vertex form equation of the parabola #f(x) = x^2 - 6x + 5#?

##### 1 Answer

Feb 20, 2016

#### Explanation:

The standard form of a quadratic function is y =

#ax^2 + bx + c# the function here

#y = x^2 - 6x + 5 " is in this form"# and by comparison : a = 1 , b = - 6 and c = 5

The vertex form of the parabola is

# y = a(x - h )^2 + k #

where ( h , k ) are the coords of the vertex.x-coord of vertex

# =( -b)/(2a) = -(-6)/2 = 3 # and y-coord =

#(3)^2 -6(3) + 5 = 9 - 18 + 5 = -4 # hence a = 1 , (h , k ) = (3 , -4 )

#rArr y = (x - 3 )^2 - 4 " is equation in vertex form "#