How do you write the vertex form equation of the parabola y=x^2+5x-6?

Jul 21, 2016

$V e r t e x \left(- \frac{5}{2} , - \frac{49}{4}\right)$

Explanation:

x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{5}{2}$
y-coordinate of vertex:
$y \left(- \frac{5}{2}\right) = \frac{25}{4} - 5 \left(\frac{5}{2}\right) - 6 = - \frac{25}{4} - \frac{24}{4} = - \frac{49}{4}$
Vertex $\left(- \frac{5}{2} , - \frac{49}{4}\right)$
Vertex form of y:
$y = {\left(x + \frac{5}{2}\right)}^{2} - \frac{49}{4}$