# How do you write the vertex form equation of the parabola y=x^2 - 8x + 3?

##### 1 Answer
Dec 4, 2017

$y + 13 = {\left(x - 4\right)}^{2}$

#### Explanation:

have

${\left(x - h\right)}^{2} = 4 p \left(y - k\right)$

$y = {x}^{2} - 8 x + 3$

completing squares

$y = {x}^{2} - 8 x + 16 - 16 + 3$

$y = {\left(x - 4\right)}^{2} - 13$

$y + 13 = {\left(x - 4\right)}^{2}$

then vertex is (h,k)

$V \left(4 , - 13\right)$