# How do you write the vertex form equation of the parabola y = (x - 3)^2 + 36?

Oct 9, 2017

The vertex is $\left(3 , 36\right)$.

#### Explanation:

The vertex of parbola $y = {\left(x - h\right)}^{2} + k$ is $\left(h , k\right)$. Comparing $y = {\left(x - 3\right)}^{2} + 36$ with $y = {\left(x - h\right)}^{2} + k$ we get $h = 3 \mathmr{and} k = 36$

So the vertex is $\left(3 , 36\right)$.

Jan 2, 2018

$\text{in vertex form}$

#### Explanation:

$\text{the equation of a parabola in "color(blue)"vertex form}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = a {\left(x - h\right)}^{2} + k} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

$\text{where "(h,k)" are the coordinates of the vertex and a}$
$\text{is a multiplier}$

$y = {\left(x - 3\right)}^{2} + 36 \leftarrow \textcolor{b l u e}{\text{in vertex form}}$