# How do you write the vertex form equation of the parabola y=(x-4)(x-8)?

Jul 7, 2018

Vertex form of equation is $y = {\left(x - 6\right)}^{2} - 4$

#### Explanation:

$y = \left(x - 4\right) \left(x - 8\right) \mathmr{and} y = {x}^{2} - 12 x + 32$ or

$y = \left({x}^{2} - 12 x + 36\right) - 36 + 32$ or

$y = {\left(x - 6\right)}^{2} - 4$ Comparing with vertex form of

equation f(x) = a(x-h)^2+k ; (h,k) being vertex we find

here $h = 6 , k = - 4$, so vertex is at $\left(6 , - 4\right)$ and vertex form of

equation is $y = {\left(x - 6\right)}^{2} - 4$

graph{(x-4)(x-8) [-10, 10, -5, 5]} [Ans]