How do you write #y-2=4(x-3)# in slope intercept form?

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Answer 1 · 2017-01-12T14:02:37

See the process for answer this question below:

The slope-intercept form of a linear equation is:

#y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b# is the y-intercept value.

Therefore, in order to transform this equation from point-slope form to slope-intercept form we must solve for #y#:

#y - 2 = (4 xx x) - (4 xx 3)#

#y - 2 = 4x - 12#

#y - 2 + color(red)(2) = 4x - 12 + color(red)(2)#

#y - 0 = 4x - 10#

#y = 4x - 10#

#y = color(red)(4)x + color(blue)(10)#