# How do you write y = 2x^2 + 2 in vertex form and identify the vertex, y intercept and x intercept?

May 24, 2015

The vertex form is:

$y - {y}_{v} = a {\left(x - {x}_{v}\right)}^{2}$.

So:

$y - 2 = 2 {x}^{2}$,

$V \left(0 , 2\right)$

To find y-intercept, we have to put $x = 0$, so $y = 2$.

To find x-intercept, we have to put $y = 0$, so $2 {x}^{2} + 2 = 0$, that is impossible.