# How do you write y= -3 (x-3) (x+2) in standard form?

$- 3 {x}^{2} + 3 x + 18$
$- 3 \left(x - 3\right) \left(x + 2\right)$
$- 3 \left({x}^{2} + 2 x - 3 x - 6\right)$
$- 3 \left({x}^{2} - x - 6\right)$
$- 3 {x}^{2} + 3 x + 18$