# How do you write y+6=-3/4(x+8) in slope intercept form?

Jul 15, 2017

See a solution process below:

#### Explanation:

The slope-intercept form of a linear equation is: $y = \textcolor{red}{m} x + \textcolor{b l u e}{b}$

Where $\textcolor{red}{m}$ is the slope and $\textcolor{b l u e}{b}$ is the y-intercept value.

Therefore we must solve this equation for $y$:

$y + 6 = - \frac{3}{4} \left(x + 8\right)$

$y + 6 = \left(- \frac{3}{4} \times x\right) + \left(- \frac{3}{4} \times 8\right)$

$y + 6 = - \frac{3}{4} x + \left(- \frac{3}{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}}} \times \textcolor{red}{\cancel{\textcolor{b l a c k}{8}}} 2\right)$

$y + 6 = - \frac{3}{4} x + \left(- 6\right)$

$y + 6 = - \frac{3}{4} x - 6$

$y + 6 - \textcolor{red}{6} = - \frac{3}{4} x - 6 - \textcolor{red}{6}$

$y + 0 = - \frac{3}{4} x - 12$

$y = \textcolor{red}{- \frac{3}{4}} x - \textcolor{b l u e}{12}$