# How do you write y= (x-2) ^2+ 6 in standard form?

Oct 2, 2017

See a solution process below:

#### Explanation:

We can use this rule to expand the term in parenthesis:

${\left(\textcolor{red}{x} - \textcolor{b l u e}{y}\right)}^{2} = {\textcolor{red}{x}}^{2} - 2 \textcolor{red}{x} \textcolor{b l u e}{y} + {\textcolor{b l u e}{y}}^{2}$

$y = {\left(\textcolor{red}{x} - \textcolor{b l u e}{2}\right)}^{2} + 6$

$y = {\textcolor{red}{x}}^{2} - \left(2 \cdot \textcolor{red}{x} \cdot \textcolor{b l u e}{2}\right) + {\textcolor{b l u e}{2}}^{2} + 6$

$y = {x}^{2} - 4 x + 4 + 6$

$y = {x}^{2} - 4 x + 10$