# How do you write y=x^2+26x+68 in vertex form?

Oct 10, 2017

Vertex form of equation is $y = {\left(x + 13\right)}^{2} - 101$

#### Explanation:

$y = {x}^{2} + 26 x + 68 \mathmr{and} y = {x}^{2} + 26 x + 169 - 169 + 68$ or

$y = {\left(x + 13\right)}^{2} - 101$ . Comparing with vertex form of equation

y=a(x-h)^2+k ; (h,k) being vertex we find here

$h = - 13 , k = - 101$. So vertex is at $\left(- 13 , - 101\right)$ and vertex

form of equation is $y = {\left(x + 13\right)}^{2} - 101$ [Ans]