How do you write y=x^2+2x-35 in vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer salamat Jun 21, 2017 see below Explanation: y = x^2 + 2x -35 use completing a square, y = (x + 1)^2 - (1)^2 - 35 y = (x + 1)^2 - 36 since (x + 1)^2 has a +ve value, it is a minimum vertex -35 at (-1, -35) Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 4632 views around the world You can reuse this answer Creative Commons License