How do you write y=x^2+4x-1 in vertex form?

$y = {x}^{2} + 4 x - 1 \Rightarrow y = {x}^{2} + 4 x + 4 - 4 - 1 \Rightarrow$
$y = {\left(x + 2\right)}^{2} - 5 \Rightarrow y + 5 = {\left(x + 2\right)}^{2}$.
The vertex is $V \left(- 2 , - 5\right)$.