# How does an ionic bond form?

Nov 5, 2016

It's a matter of one atom donating an electron (or more) to another.

#### Explanation:

Let's take sodium $N a$ that has one electron in its outer shell. Losing it, would mean that it would have the 'sacred' inert-gas configuration (full outer shell, just like Neon).
Now we have fluorine $F$. It has 7 electrons in its outer shell. If it could have just one more, it would also reach the Neon-status.

They clinch the deal, but now $N a$ has become $N {a}^{+}$ (it's positively charged, because there is one electron short for compensating the charge of the nucleus).
And $F$ becomes ${F}^{-}$ for having one too many.
These charged atoms are called ions .

And since opposites attract, $N {a}^{+}$ and ${F}^{-}$ tend to stick together, in what we call an ionic bond. And a salt (sodium fluride) has formed.