How does partial pressure affect delta G?

1 Answer
Sep 26, 2015

Answer:

#DeltaG=DeltaG^@+RTln(((P_(NH_3))^2)/(P_(N_2)*(P_(H_2))^3))#

Explanation:

The relationship between #DeltaG# and pressure is: #DeltaG=DeltaG^@+RTlnQ#

Where #Q# is the reaction quotient, that in case of a reaction involving gaseous reactants and products, pressure could be used.

For example: #N_2(g) + 3H_2(g) -> 2NH_3(g)#

The reaction quotient is: #Q=((P_(NH_3))^2)/(P_(N_2)*(P_(H_2))^3)#

Therefore, #DeltaG=DeltaG^@+RTln(((P_(NH_3))^2)/(P_(N_2)*(P_(H_2))^3))#

I recommend this video that explains this concept in details: