How does the reactivity of the element described in (a) compare with the reactivity of the element with the electron configuration [He]2s1 ?

1 Answer
Mar 20, 2018

This question is incomplete...

Explanation:

But should we have an electronic configuration of #[He]2s^(1)-=1s^(2)2s^(1)#, the NEUTRAL element necessarily corresponds to #"lithium"#, i.e. #Z=3#....

And lithium is an alkali metal, a reactive, REDUCING species, that is naturally found as its #Li^+# salt.....