# How does you find phase shift in a trigonometric function y=csc(2*Θ+π)-3?

Dec 31, 2016

#### Explanation:

The general form:

$y = \left(A\right) \csc \left(B \theta + C\right) + D$

The amplitude is A
The period, $T = \frac{2 \pi}{B}$
The phase shift, $\phi = - \frac{C}{B}$
The vertical shift is D

In the given equation:

$y = \csc \left(2 \theta + \pi\right) - 3$

$B = 2 , \mathmr{and} C = \pi$ therefore the phase shift $\phi = - \frac{\pi}{2}$