# How fast will an object with a mass of 4 kg accelerate if a force of 14 N is constantly applied to it?

Feb 27, 2016

$a = \frac{3.5 m}{s} ^ 2$

#### Explanation:

Given:

$F = 14 N$; where: $N = \frac{k g . m}{s} ^ 2$
$m = 4 k g$

Required:

a=? m/s^2

Solution:

From the formula:

$F = m a$; rearrange the formula to find the $a$
$a = \frac{F}{m}$; plug in given data
a=(14cancel(kg).m/s^2)/(4cancel(kg)
$a = 3.5 \frac{m}{s} ^ 2$

$a = 3.5 \frac{m}{s} ^ 2$