# How liters of 1.5 M HCl solution would react completely with 25 moles Ca(OH)_2?

Jul 6, 2016

Just over 33 litres

#### Explanation:

First write the balanced equation:

$C a {\left(O H\right)}_{2} \left(s\right) + 2 H C l \left(a q\right) \to C a C {l}_{2} \left(a q\right) + 2 {H}_{2} O \left(l\right)$

From this you can see that each mole of calcium hydroxide reacts with 2 moles of hydrochloric acid.

You have 25 moles of calcium hydroxide, so it means that 50 moles of hydrochloric acid is required.

The molarity of the hydrochloric acid is 1.5 M, and

$\text{number of litres" = "number of moles"/"molarity}$

This is

$\text{50 moles"/"1.5 mol/L" = "33.3 litres}$