How many air molecules are present at room temperature (27°C), and 1 atm pressure?

1 Answer
Andrea B.
Feb 19, 2018

#2,45 xx 10^22# molecules/L

Explanation:

From the ideal gases law (PV = nRT)we have:
#n/V=(P)/(RT)= (1 atm)/(0.082 (L xx atm)/(mol xx K) xx 300K)=0.046 (mol)/L#
since #1 mol = 6,02 xx 10^23# molecules
you will have #2,45 xx 10^22# molecules/L

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