# How many atoms are there in 1 mole of H2O, and how would you calculate this?

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114
Mar 29, 2017

A mole refers to $6.022 \cdot {10}^{23}$ items. ${H}_{2} O$ has 2 hydrogen atoms and 1 oxygen atom...so a total of 3 atoms in each ${H}_{2} O$.

Therefore $\left(6.022 \cdot {10}^{23}\right) \cdot$ (3 atoms) $= 18.066 \cdot {10}^{23}$

Then we need to change the answer into proper scientific notation:
$18.066 \cdot {10}^{23} = 1.8066 \cdot {10}^{24}$

Lastly, change to the proper number of significant figures. There are 4 significant figures in 6.022. Due to this we need to also have 4 significant figures in the final answer, so we would round $1.8066 \cdot {10}^{24} \to 1.807 \cdot {10}^{24}$

So, your final answer is $1.807 \cdot {10}^{24}$

Then teach the underlying concepts
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#### Explanation

Explain in detail...

#### Explanation:

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57

You calculate how many atoms are in 1 mole of $\text{H"_2"O}$ by using Avogadro's number.

#### Explanation:

You'd go about calculating this by using Avogadro's number, which links the number of atoms or molecules of a substance with the number of moles of that substance you have.

According to this relationship, every mole has $6.022 \cdot {10}^{23}$ atoms (or molecules, depending on the substance).

Since water is a molecule, 1 mole of water will always have $6.022 \cdot {10}^{23}$ molecules of water.

LIkewise, 1 mole of ${\text{O}}_{2}$, for example, will have $6.022 \cdot {10}^{23}$ molecules of diatomic oxygen, 1 mole of sulfuric acid will have $6.022 \cdot {10}^{23}$ ${H}_{2} S {O}_{4}$ molecules, 1 mole of copper will have $6.022 \cdot {10}^{23}$ atoms of copper, and so on.

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