First determine mol #"Ca"# by dividing the given grams by its molar mass (atomic weight on periodic table in g/mol). One mole of anything is #6.022xx10^23# anythings, including atoms. Once you have mol #"Ca"#, multiply it by #6.022xx10^23# #"atoms/mol"#.
#(75color(red)cancel(color(black)("g")) "Ca")/(40.078color(red)cancel(color(black)("g"))/"mol")="1.9 mol Ca"#
#1.9color(red)cancel(color(black)("mol Ca"))xx(6.022xx10^23"atoms Ca")/(1color(red)cancel(color(black)("mol Ca")))=1.1xx10^24# #"atoms Ca"# (rounded to two significant figures)