Question

How many atoms of each element of `AgNO_3` are in 0.15 mol of `AgNO_3`?

Answer 1

`9.0"x"10^22"Ag atoms"`

`9.0"x"10^22"N atoms"`

`2.7"x"10^23"O atoms"`

Explanation:

1. From 0.15mol of `AgNO_3`, we can find the moles of each element by counting how many of each element is present in the entire compound. In `AgNO_3`, there's 1 Ag, 1 N and 3 O.
2. Then, we convert from moles of each element to the number of atoms using Avogadro's number `6.02"x"10^23`.

I went ahead and set up the two steps above in 1 line for each element:
`"Ag atoms"=0.15 "mol " AgNO_3*(1 "mol " Ag)/(1 "mol " AgNO_3)*(6.02"x"10^23 "Ag atoms")/(1 "mol " Ag)=9.0"x"10^22"Ag atoms"`

`"N atoms"=0.15 "mol " AgNO_3*(1 "mol " N)/(1 "mol " AgNO_3)*(6.02"x"10^23 "N atoms")/(1 "mol " N)=9.0"x"10^22"N atoms"`

`"O atoms"=0.15 "mol " AgNO_3*(3 "mol " O)/(1 "mol " AgNO_3)*(6.02"x"10^23 "O atoms")/(1 "mol " O)=2.7"x"10^23"O atoms"`