How many CO_2 molecules are in 1.70 * 10^-2 mole of CO_2?

There are $1.70 \times {10}^{-} 2 \cdot m o l \times {N}_{A}$ $C {O}_{2}$ molecules, where.......
.......where ${N}_{A} = \text{Avogadro's Number}$ $=$ $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.
And so, $1.70 \times {10}^{-} 2 \cdot m o l \times {N}_{A} = 1.70 \times {10}^{-} 2 \cdot \cancel{m o l} \times 6.022 \times {10}^{23} \cdot \cancel{m o {l}^{-} 1}$, approx. $1.0 \times {10}^{22}$ $\text{carbon dioxide molecules}$. We get the answer as a number as required.