How many grams are present in 35.0mL of a 3.0M HCl solution?

1 Answer
Apr 13, 2018

#"3.83 g"#

Explanation:

#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#

#"3.0 M" = "n"/"0.035 L"#

#"n = 3.0 M × 0.035 L = 0.105 mol"#

# #

Molar mass of #"HCl"# is #"36.5 g/mol"#

Mass of #"0.105 mol HCl"# is

#0.105 cancel"mol" × "36.5 g"/cancel"mol" = "3.83 g"#