How many grams are there in #4.6 * 10^24# atoms of silver?

1 Answer
Apr 21, 2016

Answer:

The mass of #4.6xx10^24# atoms of silver is approximately 820 g.

Explanation:

In order to determine the mass of a given number of atoms of an element, identify the equalities between moles of the element and atoms of the element, and between moles of the element and its molar mass.

#1 "mole atoms Ag=6.022xx10"^23 "atoms Ag"#

Molar mass of Ag##=#"107.87 g/mol"#

Multiply the given atoms of silver by #(1"mol Ag")/(6.022xx23"atoms Ag")#. Then multiply times the molar mass of silver.

#4.6xx10^24cancel"atoms Ag"xx(1cancel"mol Ag")/(6.022xx10^23cancel"atoms Ag") xx(107.87"g Ag")/(1cancel"mol Ag")="820 g Ag"# rounded to two significant figures