# How many grams are there in 4.6 * 10^24 atoms of silver?

Apr 21, 2016

The mass of $4.6 \times {10}^{24}$ atoms of silver is approximately 820 g.

#### Explanation:

In order to determine the mass of a given number of atoms of an element, identify the equalities between moles of the element and atoms of the element, and between moles of the element and its molar mass.

$1 \text{mole atoms Ag=6.022xx10"^23 "atoms Ag}$

Molar mass of Ag="107.87 g/mol"

Multiply the given atoms of silver by $\left(1 \text{mol Ag")/(6.022xx23"atoms Ag}\right)$. Then multiply times the molar mass of silver.

4.6xx10^24cancel"atoms Ag"xx(1cancel"mol Ag")/(6.022xx10^23cancel"atoms Ag") xx(107.87"g Ag")/(1cancel"mol Ag")="820 g Ag" rounded to two significant figures