How many grams of AlCl3 will be produced if 7.50 moles of Al react?

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Answer 1 · 2018-04-16T12:43:07

#999.98# grams

The reaction is:

#Al^(3+) + 3Cl^(-) -> AlCl_3#

If 7.5 moles of Al was used to in this reaction, then 7.5 moles of #AlCl_3# was also produced (the ratio between #Al^(3+)# and #AlCl_3# is #1:1#)

To find the number of grams:

remember that: #"moles" = (mass)/(molar mass)#

#mass = "moles" times (molar mass)#

#mass=7.5 times (26.98 + 35.45 times3)# = #999.98# grams