Question

How many grams of ice at 0 degrees celsius & 101.3 kPa could be melted by the addition of 0.400kj of heat?

I know the answer is approximately 1.209 but I don't know how to get it.

Answer 1

`101.3 kPa` means `1 atm` pressure,at which latent heat required for conversion of ice to water at `0` degree is `79.7` calorie/gm

Suppose `m gm` of ice can be melted using `0.400 kJ` or, `0.400*10^3/4.184` calorie of heat,

so,we can write, `m*79.7=0.400*10^3/4.184`

so, `m = 1.1995 gm` i.e about `1.200 gm`